If a1 a2 a3 are in ap such that a1+a7+a16 40
WebCorrect option is C) It is given that a 1,a 2,a 3,.......,a n are in A.P and we know that: T he general form of an Arithmetic Progression is a,a+d,a+2d,a+3d and so on. Thus n th term … WebClick here👆to get an answer to your question ️ If a1, a2, a3,....an are in A.P. with common difference d, ... are in A.P. such that a 1 ... Find a Value of Expression in AP using a …
If a1 a2 a3 are in ap such that a1+a7+a16 40
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Web12 apr. 2024 · The nth term in AP series is given by the formula below: T n = a + (n – 1)d Where, n = Number of terms a = First term d = Common difference Now, the condition … Web31 jul. 2024 · Three positive integers a1,a2,a3 are in AP such that a1+a2+a3=33 and a1*a2*a3=1155.Find the integers a1,a2,a3. Advertisement Loved by our community 69 people found it helpful Saisurya Given three positive integers a1, a2,a3, in AP a1*a2*a3*=1155\ => a1+a2+a3=33..............................eq1 according to AP 2 [a2]=a1+a3 …
WebIf A1, A2, A3, .... an Are in A.P. with Common Difference D, Then the Sum of the Series Sin D [Cosec A1 Cosec A2 + Cosec A1 Cosec A3 + .... + Cosec an − 1 Cosec An] is - Mathematics Shaalaa.com Department of Pre-University Education, Karnataka PUC Karnataka Science Class 11 Textbook Solutions 11069 Important Solutions 5 Web20 mei 2024 · If a1, a2, a3 are positive numbers forming G.P. such that a5 + a7 = 12 and a4.a6 = 9, then a1a9 + a2a8 + a5 + a7 is equal to asked Feb 1 in Mathematics by …
Web13 feb. 2024 · If a1, a2, a3 are positive numbers forming G.P. such that a5 + a7 = 12 and a4.a6 = 9, then a1a9 + a2a8 + a5 + a7 is equal to asked Feb 1 in Mathematics by … Web18 nov. 2014 · if a1,a2,a3, a4001 are terms of an AP such that 1/a1a2 +1/a2a3+ +1/a4000a4001 = 10 and a2+a4000=50, then a1-a4001 is equal to (A)20 (B)30 (C)40 (D) none of ... +1/a4000a4001 = 10 and a2+a4000=50, then a1-a4001 is equal to (A)20 (B)30 (C)40 (D) none of these. Share with your friends. Share 14. We know that, ...
Web1 jul. 2024 · Best answer Correct option (D) 900 Explanation: a1 + a5 + a10 + a15 + a20 + a24 = 225 ⇒ 3 (a1 + a24) = 225 (sum of terms equidistant from beginning and end are equal) a1 + a24 = 75 Now a1 + a2 + ........ + a23 + a24 = 24/2 [a1 + a24] = 12 × 75 = 900 ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 Test Series …
Web13 okt. 2024 · 0:00 / 7:21 a1,a2,a3...,an are in A.P. such that a1 + a3 + a5 = -12 and a1a2a3=8 then: 2,308 views Oct 13, 2024 10 Dislike Share Save Doubtnut 2.1M subscribers Subscribe To ask... building memphis awards mbjWebMichelle R. Smith - staff, AP . Police block a road in North Dighton, Mass., Thursday, April 13, 2024. The FBI wants to question a 21-year-old member of the Massachusetts Air National Guard in ... building men for othersWebCorrect option is B) Given equation can be written as a 1+(a 1+3d)+(a 1+6d)+....+a 1+15d=147 ⇒6a 1+3d(1+2+..+5)=147 ⇒2a 1+15d=49 Now, a 1+a 6+a 11+a 16=4a … building memories with dad free printableWebCorrect option is B) Given equation can be written as a 1+(a 1+3d)+(a 1+6d)+....+a 1+15d=147 ⇒6a 1+3d(1+2+..+5)=147 ⇒2a 1+15d=49 Now, a 1+a 6+a 11+a 16=4a 1+5d+10d+15d =4a 1+30d=2(2a 1+15d)=2×49 =98 ∴ Option B is correct. Was this answer helpful? 0 0 Similar questions building men for life holland miWebIf a1, a2, a3,........ are terms of AP such that a1 + a5 + a10 + a15 + a20 + a24 = 225 , then the sum of first 24 terms is Class 11 >> Applied Mathematics >> Sequences and series >> Arithmetic progression >> If a1, a2, a3,........ are terms of AP s Question crown magnesiumWebClick here👆to get an answer to your question ️ Let a1, a2, a3, .... be terms of an A.P.If a1 + a2 + .... + apa1 + a2 + ..... + aq = p^2q^2, ... are in A.P. such that a 1 ... Find a Value of … building memories with kidsbuilding memories with dad printable